ASTRONOMY 102 HOUR EXAM #2

BUCKNELL UNIVERSITY

Astronomy 102

Second Hour Exam

1999 April 7


This Exam will be scored on a 100 point scale and has three parts:
a multiple choice/short answer section of 10 questions each worth 4 points
a short answer section of 2 questions worth 7 points each,
and a problem section with 3 problems, each worth 15 points.
You earn 1 point for writing your name on this exam.


Here are some quantities and relationships that you might find useful:

  • for a sphere: surface area = 4 x pi x radius2

  • distances: 1 Astronomical Unit = 1.495 x 1011 m
  •       1 parsec = 3.09 x 1016 m

  • luminosity: 1 Lo = 3.8 x 1026 W

  • for light waves: energy = h x frequency = h x c/wavelength
  •       the speed of light: c = 3 x 108 m/sec
  •       Planck's constant: h = 6.626 x 10-34 J s
  • Energy/mass conversion: energy = mass x c2

  • for blackbody emitters: intensity = sigma x temperature4
  • Stefan-Boltzmann constant:  sigma = 5.67 x 10-8 W/(m2 K4)
  •       luminosity = intensity x surface area
  •       wavelength of spectrum peak =(0.003 m K)/temperature

    Doppler formula:
                    speed of emitter     change in frequency
                    ------------------- = --------------------
                       speed of wave         rest frequency
    

  • flux: flux = luminosity/(4 x pi x distance2)

  • Mass within the orbit of an object = (speed of object)2 x (radius of orbit)/ G
  • G = 6.67 x 10-11 m3/(s2 kg)
  • The observer's triangle relation:

    alpha/57.3o = w/R


    Multiple Choice Questions (4 points each):

    Click on the highlighted letter of the correct answer to get an  explanation.

    1) High mass stars evolve off the Main Sequence faster than low mass stars because

    2) You measure the flux from two stars, star #1 in cluster Gak-6, and star #2 in cluster Bip-4. Based on their colors, you conclude that both stars have the same surface temperature. You also notice that star #1 has a higher flux than star #2. Based on this information, what can you conclude?

    3) Viewed from Lewisburg, objects on the celestial equator have a Declination of

    4) The surface temperature of a star can be determined from its

    5) Once the carbon core of a low mass star is exposed (i.e., after planetary nebula ejection), we call it a "white dwarf." Because they are very hot and very small, white dwarfs (not "dwarves") are located in the lower left of the H-R Diagram. As these objects cool, which way will they move on the H-R Diagram?

    6)The relationship between mass and luminosity for Main Sequence stars was determined from

    7) Main Sequence stars are supported against gravitational collapse by

    8) White dwarfs are supported against gravitational collapse by

    9) Why is it easier to see all of the stars in the galaxy in infrared light than in optical light?

    10) Which of the following is evidence for the presence of dark matter in the outer reaches of our galaxy?


    Short Answer (7 points each)::

    Question #1: Explain briefly how you can tell if one star cluster is older than another cluster (Hint: A diagram or two might aid your explanation.)

    ANSWER

    Question #2: Explain how Harlow Shapley was able to determine the direction and distance to the center of our galaxy, and why his correct result was different from the commonly accepted values at the time.

    ANSWER


    Problems (15 points each):

    (Show your work!! I will be very generous with partial credit!!!)


    Problem 1) The following information pertains to the bright star Canopus (sadly visible only in the southern hemisphere): Calculate the flux from this star viewed from the Earth.

    (15 points)

    ANSWER


    Problem 2) A 2He4 nucleus has a mass of 6.6488 x 10-27 kg, and a 6C12 nucleus has a mass of 1.99 x 10-26 kg.

    Part a) How much energy is generated in the following nuclear reaction (sometimes called the "triple alpha process")?

    2He4 + 2He4 + 2He4 --> 6C12

    (8 points)

    ANSWER

    Part b) How much energy is generated when a solar mass (= 2.0 x 1030 kg) of pure helium is fused into carbon in the center of a massive star?

    (8 points)

    ANSWER


    Problem 3) Below is the "rotation curve" of the Milky Way galaxy, a plot of the speed of objects as a function of their distance from the center of the galaxy. Using the data in this plot, calculate the mass contained within 6 kilo-parsecs (6 kpc, or 6000 pc) of the center of the galaxy.

    (15 points)

    ANSWER